Based on the provided information, Vo is essentially what?

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Multiple Choice

Based on the provided information, Vo is essentially what?

Explanation:
In an ideal op-amp with negative feedback, the output adjusts so the two input voltages are equal (V+ ≈ V-). If the circuit info given leads to V+ and V- being the same, the amplifier doesn’t need to drive the output away from zero to maintain that balance, so Vo settles at 0 V. That’s why Vo being essentially 0 V is the best description here. If Vo depended on a difference like 4×(V2 − V1), a nonzero output would require a nonzero input difference, which isn’t present under the stated conditions. If Vo were simply 2×V2, the output would depend on one input regardless of the other, contradicting the balanced, equal-input scenario. And Vo = −Vo would only be satisfied by Vo = 0, which is a tautology and doesn’t provide the usual circuit-based reasoning for why the output is zero under negative feedback.

In an ideal op-amp with negative feedback, the output adjusts so the two input voltages are equal (V+ ≈ V-). If the circuit info given leads to V+ and V- being the same, the amplifier doesn’t need to drive the output away from zero to maintain that balance, so Vo settles at 0 V. That’s why Vo being essentially 0 V is the best description here.

If Vo depended on a difference like 4×(V2 − V1), a nonzero output would require a nonzero input difference, which isn’t present under the stated conditions. If Vo were simply 2×V2, the output would depend on one input regardless of the other, contradicting the balanced, equal-input scenario. And Vo = −Vo would only be satisfied by Vo = 0, which is a tautology and doesn’t provide the usual circuit-based reasoning for why the output is zero under negative feedback.

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